Zapiski Nauchnykh Seminarov POMI, Investigations on linear operators and function theory. Part XVI, Tome 157 (1987), pp. 175-177
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S. R. Treil'. The resolvent of a Toeplitz operator may have arbitrary growth. Zapiski Nauchnykh Seminarov POMI, Investigations on linear operators and function theory. Part XVI, Tome 157 (1987), pp. 175-177. http://geodesic.mathdoc.fr/item/ZNSL_1987_157_a18/
@article{ZNSL_1987_157_a18,
author = {S. R. Treil'},
title = {The resolvent of {a~Toeplitz} operator may have arbitrary growth},
journal = {Zapiski Nauchnykh Seminarov POMI},
pages = {175--177},
year = {1987},
volume = {157},
language = {ru},
url = {http://geodesic.mathdoc.fr/item/ZNSL_1987_157_a18/}
}
TY - JOUR
AU - S. R. Treil'
TI - The resolvent of a Toeplitz operator may have arbitrary growth
JO - Zapiski Nauchnykh Seminarov POMI
PY - 1987
SP - 175
EP - 177
VL - 157
UR - http://geodesic.mathdoc.fr/item/ZNSL_1987_157_a18/
LA - ru
ID - ZNSL_1987_157_a18
ER -
%0 Journal Article
%A S. R. Treil'
%T The resolvent of a Toeplitz operator may have arbitrary growth
%J Zapiski Nauchnykh Seminarov POMI
%D 1987
%P 175-177
%V 157
%U http://geodesic.mathdoc.fr/item/ZNSL_1987_157_a18/
%G ru
%F ZNSL_1987_157_a18
Fix an arbitrary sequence $\{\lambda_n\}$ in the unit disc such that $\lim_n\lambda_n=1$ and any sequence $\{A_n\}$ of positive reals. Then there exists a continuous real $u$ on the unit circle such that the Toeplitz operator $T_\varphi$ (on the Hardy class $H^2$) with symbol $\varphi=e^{iu}$ satisfies $$ \|(T_\varphi-\lambda_nI)^{-1}\|>A_n $$