On primitivity of some sets of shift registers mixing digraphs
Prikladnaya Diskretnaya Matematika. Supplement, no. 10 (2017), pp. 60-62
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In this paper, we determine some conditions of primitivity and bounds of exponents $\exp\hat\Gamma$ for some sets of digraphs $\hat\Gamma=\{\Gamma_0,\dots,\Gamma_{n-1}\}$ with vertices $0,\dots,n-1$. We obtain the following results. Suppose that, for each $i\in\{0,\dots,n-1\}$, the digraph $\Gamma_i$ has the Hamiltonian cycle $(0,\dots,n-1)$ and the arc $(i,(i+l)\mod n)$, where $n\geq l>1$. Then the set $\hat\Gamma$ is primitive if and only if $\operatorname{gcd}(n,l-1)=1$; in this case, $n-1\leq\exp\hat\Gamma\leq 2n-2$. Suppose each $\Gamma_i$ also has the arc $(i,(i+\lambda)\mod n)$, $n\geq\lambda>l>1$, $i\in\{0,\dots,n-1\}$. Then the set $\hat\Gamma$ is primitive if and only if $\operatorname{gcd}(n,l-1,\lambda-1)=1$; in this case, $\exp\hat\Gamma\geq(\sqrt{8n+1}-3)/2$ and if $\operatorname{gcd}(n,l-1)=1$, then the exponent is at most $n-1+\max\{b,n-b+1\}$, where $b=(\lambda-1)(l-1)^{\varphi(n)-1}\mod n$ and $\varphi(n)$ denotes Euler's totient function. At last, suppose $n$ is even and each $\Gamma_i$ has the cycle $(0,\dots,n-1)$ and the arc $(i,(i+l)\mod n)$ if $i$ is even, the cycle $(n-1,\dots,0)$ and the arc $(i,(i+\lambda)\mod n)$ if $i$ is odd. Then the set $\hat\Gamma$ is primitive and its exponent is at most $2n-2$ if $\operatorname{gcd}(n,l-1)=1$ or $\operatorname{gcd}(n,\lambda+1)=1$.
Keywords:
primitivity of digraphs set, exponent of digraph, exponent of digraphs set.
Y. E. Avezova. On primitivity of some sets of shift registers mixing digraphs. Prikladnaya Diskretnaya Matematika. Supplement, no. 10 (2017), pp. 60-62. http://geodesic.mathdoc.fr/item/PDMA_2017_10_a24/
@article{PDMA_2017_10_a24,
author = {Y. E. Avezova},
title = {On primitivity of some sets of shift registers mixing digraphs},
journal = {Prikladnaya Diskretnaya Matematika. Supplement},
pages = {60--62},
year = {2017},
number = {10},
language = {ru},
url = {http://geodesic.mathdoc.fr/item/PDMA_2017_10_a24/}
}
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