Dalʹnevostočnyj matematičeskij žurnal, Tome 23 (2023) no. 1, pp. 16-26
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M. D. Dmitriev; F. Yu. Ozhegov. Covering of a rectangle with squares from both sides. Dalʹnevostočnyj matematičeskij žurnal, Tome 23 (2023) no. 1, pp. 16-26. http://geodesic.mathdoc.fr/item/DVMG_2023_23_1_a2/
@article{DVMG_2023_23_1_a2,
author = {M. D. Dmitriev and F. Yu. Ozhegov},
title = {Covering of a rectangle with squares from both sides},
journal = {Dalʹnevosto\v{c}nyj matemati\v{c}eskij \v{z}urnal},
pages = {16--26},
year = {2023},
volume = {23},
number = {1},
language = {ru},
url = {http://geodesic.mathdoc.fr/item/DVMG_2023_23_1_a2/}
}
TY - JOUR
AU - M. D. Dmitriev
AU - F. Yu. Ozhegov
TI - Covering of a rectangle with squares from both sides
JO - Dalʹnevostočnyj matematičeskij žurnal
PY - 2023
SP - 16
EP - 26
VL - 23
IS - 1
UR - http://geodesic.mathdoc.fr/item/DVMG_2023_23_1_a2/
LA - ru
ID - DVMG_2023_23_1_a2
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%A F. Yu. Ozhegov
%T Covering of a rectangle with squares from both sides
%J Dalʹnevostočnyj matematičeskij žurnal
%D 2023
%P 16-26
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%U http://geodesic.mathdoc.fr/item/DVMG_2023_23_1_a2/
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%F DVMG_2023_23_1_a2
The paper provides an elementary proof of Kenyon's theorem that periodic tiling of a plane by squares with periods $(1,0)$ and $(0,\lambda)$ is possible only if $\lambda=p\pm\sqrt{q^2 - r^2}$ for some rational $p\geq q\geq r\geq 0$. A similar new result is proved about covering of a rectangle with squares from both sides in one layer. The paper also proves a necessary and sufficient condition for covering with equal squares.
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