Geodesic
${\bf Bad}(s,t)$ is hyperplane absolute winning
Erez Nesharim 1   ; David Simmons 2
1 School of Mathematical Sciences Tel Aviv University Ramat Aviv Tel Aviv 6997801, Israel
2 Department of Mathematics Ohio State University 231 W. 18th Avenue Columbus, OH 43210-1174, U.S.A.
Acta Arithmetica, Tome 164 (2014) no. 2, pp. 145-152 Cet article a éte moissonné depuis la source Institute of Mathematics Polish Academy of Sciences

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J. An proved that for any $s,t \geq 0$ such that $s + t = 1$, $\mathop {\bf Bad}\nolimits (s,t)$ is $(34\sqrt 2)^{-1}$-winning for Schmidt's game. We show that using the main lemma from [An] one can derive a stronger result, namely that $\mathop {\bf Bad}\nolimits (s,t)$ is hyperplane absolute winning in the sense of [BFKRW]. As a consequence, one can deduce the full Hausdorff dimension of $\mathop {\bf Bad}\nolimits (s,t)$ intersected with certain fractals.
DOI : 10.4064/aa164-2-4
Keywords: proved geq mathop bad nolimits sqrt winning schmidts game using main lemma derive stronger result namely mathop bad nolimits hyperplane absolute winning sense bfkrw consequence deduce full hausdorff dimension mathop bad nolimits intersected certain fractals

Erez Nesharim  1   ; David Simmons  2

1 School of Mathematical Sciences Tel Aviv University Ramat Aviv Tel Aviv 6997801, Israel
2 Department of Mathematics Ohio State University 231 W. 18th Avenue Columbus, OH 43210-1174, U.S.A. 
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Erez Nesharim; David Simmons. ${\bf Bad}(s,t)$ is hyperplane absolute winning. Acta Arithmetica, Tome 164 (2014) no. 2, pp. 145-152. doi: 10.4064/aa164-2-4

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