On spanning trees without vertices of degree 2 in plane triangulations
Zapiski Nauchnykh Seminarov POMI, Combinatorics and graph theory. Part X, Tome 475 (2018), pp. 93-98
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Let $G$ be a $2$-connected plane graph such that at most one its face is not a triangle. It is proved that $G$ has a spanning tree without vertices of degree $2$.
@article{ZNSL_2018_475_a3,
author = {D. V. Karpov},
title = {On spanning trees without vertices of degree 2 in plane triangulations},
journal = {Zapiski Nauchnykh Seminarov POMI},
pages = {93--98},
year = {2018},
volume = {475},
language = {ru},
url = {http://geodesic.mathdoc.fr/item/ZNSL_2018_475_a3/}
}
D. V. Karpov. On spanning trees without vertices of degree 2 in plane triangulations. Zapiski Nauchnykh Seminarov POMI, Combinatorics and graph theory. Part X, Tome 475 (2018), pp. 93-98. http://geodesic.mathdoc.fr/item/ZNSL_2018_475_a3/
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