Bounds of a~number of leaves of spanning trees
Zapiski Nauchnykh Seminarov POMI, Combinatorics and graph theory. Part III, Tome 391 (2011), pp. 18-34
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We prove that every connected graph with $s$ vertices of degree not 2 has a spanning tree with at least $\frac14(s-2)+2$ leaves.
Let $G$ be a connected graph of girth $g$ with $v$ vertices. Let maximal chain of successively adjacent vertices of degree 2 in the graph $G$ does not exceed $k\ge1$. We prove that $G$ has a spanning tree with at least $\alpha_{g,k}(v(G)-k-2)+2$ leaves, where $\alpha_{g,k}=\frac{[\frac{g+1}2]}{[\frac{g+1}2](k+3)+1}$ for $k$; $\alpha_{g,k}(v(G)-k-2)+2$ for $k\ge g-2$.
We present infinite series of examples showing that all these bounds are exact.
@article{ZNSL_2011_391_a1,
author = {A. V. Bankevich and D. V. Karpov},
title = {Bounds of a~number of leaves of spanning trees},
journal = {Zapiski Nauchnykh Seminarov POMI},
pages = {18--34},
publisher = {mathdoc},
volume = {391},
year = {2011},
language = {ru},
url = {http://geodesic.mathdoc.fr/item/ZNSL_2011_391_a1/}
}
A. V. Bankevich; D. V. Karpov. Bounds of a~number of leaves of spanning trees. Zapiski Nauchnykh Seminarov POMI, Combinatorics and graph theory. Part III, Tome 391 (2011), pp. 18-34. http://geodesic.mathdoc.fr/item/ZNSL_2011_391_a1/