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Integrability of trigonometric series. The estimation of the integral modulus of continuity
Sbornik. Mathematics, Tome 20 (1973) no. 4, pp. 557-573 Cet article a éte moissonné depuis la source Math-Net.Ru

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Let $a_m$ tend to zero and let the quantities \begin{align*} B_n&=\sum_{m=1}^n\biggl(\frac mn\biggr)^k|\Delta a_m|+\sum_{m=n+1}^\infty|\Delta a_m|+ \\ &\qquad+\sum_{m=2}^n\biggl(\frac mn\biggr)^k\biggl|\sum_{i=1}^{[m/2]}\frac{\Delta a_{m-i}-\Delta a_{m+i}}i\biggr|+\sum_{m=n+1}^\infty\biggl|\sum_{i=1}^{[m/2]}\frac{\Delta a_{m-i}-\Delta a_{m+i}}i\biggr|. \end{align*} be finite. We put $f(x)=\frac{a_0}2+\sum_{m=1}^\infty a_m\cos mx$ and $g(x)=\sum_{m=1}^\infty a_m\sin mx$. It is shown that the integral modulus of continuity of $k$th order for the function $f$ satisfies the estimate $\omega_k\bigl(f,\frac1n\bigr)_L=O(B_n)$, and that if the series $\sum\frac{|a_m|}m$, converges then $$ \omega_k\biggl(g,\frac1n\biggr)_L=\frac{2^k}\pi\sum_{m=n}^\infty\frac{|a_m|}m+O(B_n). $$ Bibliography: 10 titles. 
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     title = {Integrability of trigonometric series. {The} estimation of the integral modulus of continuity},
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}
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S. A. Telyakovskii. Integrability of trigonometric series. The estimation of the integral modulus of continuity. Sbornik. Mathematics, Tome 20 (1973) no. 4, pp. 557-573. http://geodesic.mathdoc.fr/item/SM_1973_20_4_a4/

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