Products of ultrafilters and irresolvable spaces
Sbornik. Mathematics, Tome 19 (1973) no. 1, pp. 105-115
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A space dense in itself is said to be $k$-resolvable if there exists a system of cardinality $k$ of disjoint dense subsets. The main results of the paper can be formulated as follows:
1. If there exists a countably-centered free ultrafilter, then there are dense in themselves $T_1$-spaces whose product is irresolvable.
2. Any sets $X$ and $Y$ support irresolvable $T_1$-topologies whose product is maximally resolvable.
3. Assuming the continuum hypothesis, an ultrafilter whose cartesian square is dominated by only three ultrafilters is constructed on a countable set.
4. If a set of uncountable cardinality supports an ultrafilter whose square is dominated by exactly three ultrafilters, then its cardinality is measurable.
A number of problems are posed.
Bibliography: 9 titles.
@article{SM_1973_19_1_a6,
author = {V. I. Malykhin},
title = {Products of ultrafilters and irresolvable spaces},
journal = {Sbornik. Mathematics},
pages = {105--115},
publisher = {mathdoc},
volume = {19},
number = {1},
year = {1973},
language = {en},
url = {http://geodesic.mathdoc.fr/item/SM_1973_19_1_a6/}
}
V. I. Malykhin. Products of ultrafilters and irresolvable spaces. Sbornik. Mathematics, Tome 19 (1973) no. 1, pp. 105-115. http://geodesic.mathdoc.fr/item/SM_1973_19_1_a6/