Voir la notice de l'article provenant de la source Math-Net.Ru
@article{MMKZ_2008_3_a11, author = {M. G. Volynskaya}, title = {{\CYRO}{\cyrb} {\cyro}{\cyrd}{\cyrn}{\cyro}{\cyrishrt} {\cyrk}{\cyrr}{\cyra}{\cyre}{\cyrv}{\cyro}{\cyrishrt} {\cyrz}{\cyra}{\cyrd}{\cyra}{\cyrch}{\cyre} {\cyrd}{\cyrl}{\cyrya} {\cyru}{\cyrr}{\cyra}{\cyrv}{\cyrn}{\cyre}{\cyrn}{\cyri}{\cyrya} {\cyrs}{\cyrm}{\cyre}{\cyrsh}{\cyra}{\cyrn}{\cyrn}{\cyro}{\cyrg}{\cyro} {\cyrt}{\cyri}{\cyrp}{\cyra} {\cyrv} {\cyrp}{\cyrr}{\cyrya}{\cyrm}{\cyro}{\cyru}{\cyrg}{\cyro}{\cyrl}{\cyrsftsn}{\cyrn}{\cyri}{\cyrk}{\cyre}}, journal = {Matematicheskoe Modelirovanie i Kraevye Zadachi}, pages = {48--51}, publisher = {mathdoc}, volume = {3}, year = {2008}, language = {ru}, url = {http://geodesic.mathdoc.fr/item/MMKZ_2008_3_a11/} }
M. G. Volynskaya. Об одной краевой задаче для уравнения смешанного типа в прямоугольнике. Matematicheskoe Modelirovanie i Kraevye Zadachi, Proceedings of the Fifth All-Russian Scientific Conference with international participation (29–31 May 2008). Part 3, Tome 3 (2008), pp. 48-51. http://geodesic.mathdoc.fr/item/MMKZ_2008_3_a11/