Geodesic
A commutativity theorem for associative rings
Archivum mathematicum, Tome 31 (1995) no. 3, pp. 201-204 Cet article a éte moissonné depuis la source Czech Digital Mathematics Library

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Let $m > 1, s\geq 1$ be fixed positive integers, and let $R$ be a ring with unity $1$ in which for every $x$ in $R$ there exist integers $p = p(x) \geq 0, q = q(x) \geq 0, n = n(x) \geq 0, r = r(x) \geq 0 $ such that either $ x^{p}[x^{n},y]x^{q} = x^{r}[x,y^{m}]y^{s} $ or $ x^{p}[x^{n},y]x^{q} = y^{s}[x,y^{m}]x^{r} $ for all $ y \in R $. In the present paper it is shown that $R$ is commutative if it satisfies the property $Q(m)$ (i.e. for all $x,y \in R, m[x,y] = 0$ implies $[x,y] = 0$).
Let $m > 1, s\geq 1$ be fixed positive integers, and let $R$ be a ring with unity $1$ in which for every $x$ in $R$ there exist integers $p = p(x) \geq 0, q = q(x) \geq 0, n = n(x) \geq 0, r = r(x) \geq 0 $ such that either $ x^{p}[x^{n},y]x^{q} = x^{r}[x,y^{m}]y^{s} $ or $ x^{p}[x^{n},y]x^{q} = y^{s}[x,y^{m}]x^{r} $ for all $ y \in R $. In the present paper it is shown that $R$ is commutative if it satisfies the property $Q(m)$ (i.e. for all $x,y \in R, m[x,y] = 0$ implies $[x,y] = 0$).
Classification : 16R50, 16U70, 16U80
Keywords: polynomial identity; nilpotent element; commutator ideal; associative ring; torsion free ring; center; commutativity 
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     author = {Ashraf, Mohammad},
     title = {A commutativity theorem for associative rings},
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     language = {en},
     url = {http://geodesic.mathdoc.fr/item/ARM_1995_31_3_a3/}
}
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Ashraf, Mohammad. A commutativity theorem for associative rings. Archivum mathematicum, Tome 31 (1995) no. 3, pp. 201-204. http://geodesic.mathdoc.fr/item/ARM_1995_31_3_a3/

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