The supersolvable residual of a finite group factorized by pairwise permutable seminormal subgroups
Algebra i logika, Tome 60 (2021) no. 3, pp. 313-326

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A subgroup $A$ is seminormal in a finite group $G$ if there exists a subgroup $B$ such that $G=AB$ and $AX$ is a subgroup for each subgroup $X$ from $B$. We study a group $G=G_1G_2\ldots G_n$ with pairwise permutable supersolvable groups $G_1,\ldots,G_n$ such that $G_i$ and $G_j$ are seminormal in $G_iG_j$ for any $i,j\in\{1,\ldots,n\}$, $i\neq j$. It is stated that $G^\mathfrak U=(G^\prime)^\mathfrak N$. Here $\mathfrak N$ and $\mathfrak U$ are the formations of all nilpotent and supersolvable groups, and $H^\mathfrak X$ and $H^{\prime}$ are the $\mathfrak X$-residual and the derived subgroup, respectively, of a group $H$. It is proved that a group $G=G_1G_2\ldots G_n$ with pairwise permutable subgroups $G_1,\ldots,G_n$ is supersolvable provided that all Sylow subgroups of $G_i$ and $G_j$ are seminormal in $G_iG_j$ for any $i,j\in\{1,\ldots,n\}$, $i\neq j$.
Mots-clés : supersolvable group
Keywords: nilpotent group, seminormal subgroup, derived subgroup, $\mathfrak X$-residual, Sylow subgroup.
@article{AL_2021_60_3_a4,
     author = {A. A. Trofimuk},
     title = {The supersolvable residual of a finite group factorized by pairwise permutable seminormal subgroups},
     journal = {Algebra i logika},
     pages = {313--326},
     publisher = {mathdoc},
     volume = {60},
     number = {3},
     year = {2021},
     language = {ru},
     url = {http://geodesic.mathdoc.fr/item/AL_2021_60_3_a4/}
}
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A. A. Trofimuk. The supersolvable residual of a finite group factorized by pairwise permutable seminormal subgroups. Algebra i logika, Tome 60 (2021) no. 3, pp. 313-326. http://geodesic.mathdoc.fr/item/AL_2021_60_3_a4/