Almost tiling of the Boolean lattice with copies of a poset
The electronic journal of combinatorics, Tome 25 (2018) no. 1
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Let $P$ be a partially ordered set. If the Boolean lattice $(2^{[n]},\subset)$ can be partitioned into copies of $P$ for some positive integer $n$, then $P$ must satisfy the following two trivial conditions:(1) the size of $P$ is a power of $2$,(2) $P$ has a unique maximal and minimal element.Resolving a conjecture of Lonc, it was shown by Gruslys, Leader and Tomon that these conditions are sufficient as well.In this paper, we show that if $P$ only satisfies condition (2), we can still almost partition $2^{[n]}$ into copies of $P$. We prove that if $P$ has a unique maximal and minimal element, then there exists a constant $c=c(P)$ such that all but at most $c$ elements of $2^{[n]}$ can be covered by disjoint copies of $P$.
DOI : 10.37236/6636
Classification : 05B45, 06A07
Mots-clés : tiling, Boolean lattice, poset

István Tomon  1

1 École Polytechnique Fédérale de Lausanne
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     author = {Istv\'an Tomon},
     title = {Almost tiling of the {Boolean} lattice with copies of a poset},
     journal = {The electronic journal of combinatorics},
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     doi = {10.37236/6636},
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István Tomon. Almost tiling of the Boolean lattice with copies of a poset. The electronic journal of combinatorics, Tome 25 (2018) no. 1. doi: 10.37236/6636

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