Drawing Hamiltonian cycles with no large angles
The electronic journal of combinatorics, Tome 19 (2012) no. 2
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Let $n \geq 4$ be even. It is shown that every set $S$ of $n$ points in the plane can be connected by a (possibly self-intersecting) spanning tour (Hamiltonian cycle) consisting of $n$ straight-line edges such that the angle between any two consecutive edges is at most $2\pi/3$. For $n=4$ and $6$, this statement is tight. It is also shown that every even-element point set $S$ can be partitioned into at most two subsets, $S_1$ and $S_2$, each admitting a spanning tour with no angle larger than $\pi/2$. Fekete and Woeginger conjectured that for sufficiently large even $n$, every $n$-element set admits such a spanning tour. We confirm this conjecture for point sets in convex position. A much stronger result holds for large point sets randomly and uniformly selected from an open region bounded by finitely many rectifiable curves: for any $\epsilon>0$, these sets almost surely admit a spanning tour with no angle larger than $\epsilon$.
DOI : 10.37236/2356
Classification : 05C45
Mots-clés : Hamiltonian cycle, turning angle, geometric graph

Adrian Dumitrescu  1   ; János Pach  2   ; Géza Tóth  3

1 University of Wisconsin-Milwaukee
2 Ecole Polytechnique Fédérale de Lausanne and City College, New York
3 Alfred Rényi Institute of Mathematics
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     title = {Drawing {Hamiltonian} cycles with no large angles},
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     year = {2012},
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Adrian Dumitrescu; János Pach; Géza Tóth. Drawing Hamiltonian cycles with no large angles. The electronic journal of combinatorics, Tome 19 (2012) no. 2. doi: 10.37236/2356

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