Counting lattice paths by Narayana polynomials
The electronic journal of combinatorics, Tome 7 (2000)
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Let $d(n)$ count the lattice paths from $(0,0)$ to $(n,n)$ using the steps (0,1), (1,0), and (1,1). Let $e(n)$ count the lattice paths from $(0,0)$ to $(n,n)$ with permitted steps from the step set ${\bf N} \times {\bf N} - \{(0,0)\}$, where ${\bf N}$ denotes the nonnegative integers. We give a bijective proof of the identity $e(n) = 2^{n-1} d(n)$ for $n \ge 1$. In giving perspective for our proof, we consider bijections between sets of lattice paths defined on various sets of permitted steps which yield path counts related to the Narayana polynomials.
DOI : 10.37236/1518
Classification : 05A15
Mots-clés : Delannoy numbers, Narayana numbers, lattice paths
@article{10_37236_1518,
     author = {Robert A. Sulanke},
     title = {Counting lattice paths by {Narayana} polynomials},
     journal = {The electronic journal of combinatorics},
     year = {2000},
     volume = {7},
     doi = {10.37236/1518},
     zbl = {0953.05006},
     url = {http://geodesic.mathdoc.fr/articles/10.37236/1518/}
}
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Robert A. Sulanke. Counting lattice paths by Narayana polynomials. The electronic journal of combinatorics, Tome 7 (2000). doi: 10.37236/1518

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