Solving Maker-Breaker Games on 5-Uniform Hypergraphs is PSPACE-Complete
The electronic journal of combinatorics, Tome 32 (2025) no. 4
Let $(X, \mathcal{F})$ be a hypergraph. The Maker-Breaker game on $(X, \mathcal{F})$ is a combinatorial game between two players, Maker and Breaker. The players take turns claiming vertices from $X$ that have not yet been claimed. Maker wins if she manages to claim all vertices of some hyperedge $F \in \mathcal{F}$. Breaker wins if he claims at least one vertex in every hyperedge. Rahman and Watson proved in 2021 that, even when only Maker-Breaker games on 6-uniform hypergraphs are considered, the decision problem of determining which player has a winning strategy is PSPACE-complete. They also showed that the problem is NL-hard when considering hypergraphs of rank 5. In this paper, we improve the latter result by showing that deciding who wins Maker-Breaker games on 5-uniform hypergraphs is still a PSPACE-complete problem. We achieve this by polynomial transformation from the problem of solving the generalized geography game on bipartite digraphs with vertex degrees 3 or less, which is known to be PSPACE-complete.
@article{10_37236_13920,
author = {Finn Koepke},
title = {Solving {Maker-Breaker} {Games} on {5-Uniform} {Hypergraphs} is {PSPACE-Complete}},
journal = {The electronic journal of combinatorics},
year = {2025},
volume = {32},
number = {4},
doi = {10.37236/13920},
url = {http://geodesic.mathdoc.fr/articles/10.37236/13920/}
}
Finn Koepke. Solving Maker-Breaker Games on 5-Uniform Hypergraphs is PSPACE-Complete. The electronic journal of combinatorics, Tome 32 (2025) no. 4. doi: 10.37236/13920
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