If L1 and L2 are two Brunnian links with all pairwise linking numbers 0, then we show that L1 and L2 are equivalent if and only if they have homeomorphic complements. In particular, this holds for all Brunnian links with at least three components. If L1 is a Brunnian link with all pairwise linking numbers 0, and the complement of L2 is homeomorphic to the complement of L1, then we show that L2 may be obtained from L1 by a sequence of twists around unknotted components. Finally, we show that for any positive integer n, an algorithm for detecting an n–component unlink leads immediately to an algorithm for detecting an unlink of any number of components. This algorithmic generalization is conceptually simple, but probably computationally impractical.
Mangum, Brian S  1 ; Stanford, Theodore  2
@article{10_2140_agt_2001_1_143,
author = {Mangum, Brian S and Stanford, Theodore},
title = {Brunnian links are determined by their complements},
journal = {Algebraic and Geometric Topology},
pages = {143--152},
year = {2001},
volume = {1},
number = {1},
doi = {10.2140/agt.2001.1.143},
url = {http://geodesic.mathdoc.fr/articles/10.2140/agt.2001.1.143/}
}
TY - JOUR AU - Mangum, Brian S AU - Stanford, Theodore TI - Brunnian links are determined by their complements JO - Algebraic and Geometric Topology PY - 2001 SP - 143 EP - 152 VL - 1 IS - 1 UR - http://geodesic.mathdoc.fr/articles/10.2140/agt.2001.1.143/ DO - 10.2140/agt.2001.1.143 ID - 10_2140_agt_2001_1_143 ER -
Mangum, Brian S; Stanford, Theodore. Brunnian links are determined by their complements. Algebraic and Geometric Topology, Tome 1 (2001) no. 1, pp. 143-152. doi: 10.2140/agt.2001.1.143
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