Geodesic
The diophantine equation $x^2+2^a\cdot 17^b=y^n$
Czechoslovak Mathematical Journal, Tome 62 (2012) no. 3, pp. 645-654
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Let $\mathbb {Z}$, $ \mathbb {N}$ be the sets of all integers and positive integers, respectively. Let $p$ be a fixed odd prime. Recently, there have been many papers concerned with solutions $(x, y, n, a, b)$ of the equation $ x^2+2^ap^b=y^n$, $x, y, n\in \mathbb {N}$, $\gcd (x, y)=1$, $n\geq 3$, $a, b\in \mathbb {Z}$, $a\geq 0$, $b\geq 0. $ And all solutions of it have been determined for the cases $p=3$, $p=5$, $p=11$ and $p=13$. In this paper, we mainly concentrate on the case $p=3$, and using certain recent results on exponential diophantine equations including the famous Catalan equation, all solutions $(x, y, n, a, b)$ of the equation $x^2+2^a\cdot 17^b=y^n$, $x, y, n\in \mathbb {N}$, $\gcd (x, y)=1$, $n\geq 3$, $a, b\in \mathbb {Z}$, $ a\geq 0$, $ b\geq 0$, are determined.
Let $\mathbb {Z}$, $ \mathbb {N}$ be the sets of all integers and positive integers, respectively. Let $p$ be a fixed odd prime. Recently, there have been many papers concerned with solutions $(x, y, n, a, b)$ of the equation $ x^2+2^ap^b=y^n$, $x, y, n\in \mathbb {N}$, $\gcd (x, y)=1$, $n\geq 3$, $a, b\in \mathbb {Z}$, $a\geq 0$, $b\geq 0. $ And all solutions of it have been determined for the cases $p=3$, $p=5$, $p=11$ and $p=13$. In this paper, we mainly concentrate on the case $p=3$, and using certain recent results on exponential diophantine equations including the famous Catalan equation, all solutions $(x, y, n, a, b)$ of the equation $x^2+2^a\cdot 17^b=y^n$, $x, y, n\in \mathbb {N}$, $\gcd (x, y)=1$, $n\geq 3$, $a, b\in \mathbb {Z}$, $ a\geq 0$, $ b\geq 0$, are determined.
DOI : 10.1007/s10587-012-0056-z
Classification : 11D61
Keywords: exponential diophantine equation; modular approach; arithmetic properties of Lucas numbers 
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Gou, Su; Wang, Tingting. The diophantine equation $x^2+2^a\cdot 17^b=y^n$. Czechoslovak Mathematical Journal, Tome 62 (2012) no. 3, pp. 645-654. doi: 10.1007/s10587-012-0056-z

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